Find with path compression

🔸 Approach 3: Recursive Reverse Comparison

--------------------------------------------------- 🔸 Approach 1: Brute Force using Modulo - Loop through each digit using modulo - Check if digit !=

🔸 Approach 1: Brute Force Method Loop from 1 to min(n1, n2) and check for all numbers that divide both. Track the largest such number. 🧠 Logic: - Sta

🔸 Approach 2: Euclidean Algorithm Efficient method using modulo (%). Key Property: gcd(a, b) = gcd(b, a % b) Repeat until one number becomes 0. The o

🔸 Approach 3: Recursive Check

🔸 Approach 1: Brute Force Loop through all numbers from 1 to n and check if they divide n

🔸 Approach 2: Optimized Square Root Approach Divisors occur in pairs (i, n/i), and we only need to loop till sqrt(n)

🔸 Approach 4: Recursive Method Recursively check and print divisors from 1 to n

🔸 Approach 3: Using a Vector + Sorting Collect divisors in a vector and sort them for ordered output

🔸 Approach 4: For Loop (Alternative Math)

🔸 Approach 1: While Loop (Mathematical)

🔸 Approach 2: Recursion

🔸 Approach 3: String Reversal

------------------------------------------ 🔹 Approach 3: Recursive - Calculates sum of digits raised to total digit count - Uses recursion for summati

--------------------------------------------------- 🔸 Approach 2: Count Total Digits Using log10 - Just counts total digits, not the ones that divide

Helper function to add two reversed lists

Helper function to calculate the height of a subtree and update the maximum diameter found so far

Helper to calculate total hours needed at a given eating speed

Main function - using the most optimal approach

Approach 2: Memoization (Top-Down DP) Time: O(amount * coins), Space: O(amount * coins) - memoization table

Approach 4: Space Optimization Time: O(amount * coins), Space: O(amount) - 1D DP array

Approach 1: Recursion (Brute Force) Time: O(2^(amount+coins)), Space: O(amount) - recursion stack

Approach 3: Tabulation (Bottom-Up DP) Time: O(amount * coins), Space: O(amount * coins) - 2D DP array

Main function - using the most optimal approach

Approach 2: Memoization (Top-Down DP) Time: O(n), Space: O(n) - memoization table + recursion stack

Approach 4: Space Optimization Time: O(n), Space: O(1) - only two variables

Approach 1: Recursion (Brute Force) Time: O(2^n), Space: O(n) - recursion stack

Approach 3: Tabulation (Bottom-Up DP) Time: O(n), Space: O(n) - DP array

Main function - using the most optimal approach

Approach 2: Memoization (Top-Down DP) Time: O(S * n), Space: O(S) - memoization table + recursion stack

Approach 4: Space Optimization Time: O(S * n), Space: O(S) - already optimal for this problem

Approach 1: Recursion (Brute Force) Time: O(S^n) where S is amount, Space: O(S) - recursion stack

Approach 3: Tabulation (Bottom-Up DP) Time: O(S * n), Space: O(S) - DP array

Decodes your encoded data to tree.

Helper function to deserialize tree using preorder traversal

DFS approach: traverse right first, then left

DFS helper function to count good nodes