(ListNode head)
| 11 | */ |
| 12 | public class Solution { |
| 13 | public boolean hasCycle(ListNode head) { |
| 14 | |
| 15 | if (head == null){ |
| 16 | return false; |
| 17 | } |
| 18 | |
| 19 | ListNode slowPtr = head; |
| 20 | ListNode fastPtr = head; |
| 21 | |
| 22 | /** Approach |
| 23 | |
| 24 | // 1. if no cycle exists AND |
| 25 | // a. if there are even number of nodes then fast pointer will be pointing to null. |
| 26 | // b. else there are odd number of nodes then fast pointer will be pointing to last node. |
| 27 | |
| 28 | // 2. if slow pointer meet fast pointer that interprets there exists a loop |
| 29 | */ |
| 30 | |
| 31 | while (fastPtr != null && fastPtr.next != null) { |
| 32 | |
| 33 | // move slow pointer one node at a time |
| 34 | slowPtr = slowPtr.next; |
| 35 | |
| 36 | // move fast pointer two nodes at a time |
| 37 | fastPtr = fastPtr.next.next; |
| 38 | |
| 39 | if (slowPtr == fastPtr) |
| 40 | return true; |
| 41 | } |
| 42 | |
| 43 | return false; |
| 44 | } |
| 45 | } |
nothing calls this directly
no outgoing calls
no test coverage detected