返回与另一个PCollection中不相同的元素 Args: other (PCollection): 另一个PCollection Returns: PCollection: 表示结果的PCollection >>> a = _pipeline.parallelize([1, 1, 2, 3]) >>> b = _pipeline.parallelize([1, 1, 2, 2]) >>> a.diff(b).get() [(2,
(self, other)
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no outgoing calls