对于给定的PCollection1和PCollection2，返回两者不相同的元素 Args: pcollection1 (PCollection): 输入1 pcollection2 (PCollection): 输入2 Returns: PCollection: 表示差异的PCollection >>> from bigflow import transforms >>> a = _pipeline.parallelize([1, 1, 2, 3]) >>> b = _pipeline.par
(pcollection1, pcollection2)
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