Function fizzbuzz

Hackerrank_problems/FizzBuzz/Solution2.py:1–1 · view source on GitHub ↗

(x)

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1	def fizzbuzz(x):
2	"""FizzBuzz challenge
3	scan through 1 to 100 and tell which numbers are fizz, buzz, or fizzbuzz
4	fizz - a number divisible by 3

Solution2.pyFile · 0.85

no outgoing calls

no test coverage detected