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hub / github.com/Vishruth-S/CompetitiveCode / Solution2.py

File Solution2.py

Hackerrank_problems/FizzBuzz/Solution2.py:None–None  ·  view source on GitHub ↗

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1def fizzbuzz(x):
2"""FizzBuzz challenge
3scan through 1 to 100 and tell which numbers are fizz, buzz, or fizzbuzz
4fizz - a number divisible by 3

Callers

nothing calls this directly

Calls 1

fizzbuzzFunction · 0.85

Tested by

no test coverage detected