Function _get_namespace_path

ci/lint_cpp/test_unity_build.py:198–214

Get the namespace path for a file (path after src/). Args: file_path: Path to the file src_dir: Path to the src directory Returns: Namespace path as string (e.g., "platforms/arm") or None if not in src/

(file_path: Path, src_dir: Path)

def _get_namespace_path(file_path: Path, src_dir: Path) -> str | None:
    """
    Get the namespace path for a file (path after src/).

    Args:
        file_path: Path to the file
        src_dir: Path to the src directory

    Returns:
        Namespace path as string (e.g., "platforms/arm") or None if not in src/
    """
    try:
        src_index = file_path.parts.index(SRC_DIR_NAME)
        namespace_parts = file_path.parts[src_index + 1 : -1]  # Exclude filename
        return "/".join(namespace_parts)
    except (ValueError, IndexError):
        return None


def _calculate_include_depth(included_path: str, expected_prefix: str) -> int: