Function openFile

lib/core/common.py:3802–3828

Returns file handle of a given filename >>> "openFile" in openFile(__file__).read() True >>> b"openFile" in openFile(__file__, "rb", None).read() True

(filename, mode='r', encoding=UNICODE_ENCODING, errors="reversible", buffering=1)

            logger.debug(msg)

def openFile(filename, mode='r', encoding=UNICODE_ENCODING, errors="reversible", buffering=1):  # "buffering=1" means line buffered (Reference: http://stackoverflow.com/a/3168436)
    """
    Returns file handle of a given filename

    >>> "openFile" in openFile(__file__).read()
    True
    >>> b"openFile" in openFile(__file__, "rb", None).read()
    True
    """

    # Reference: https://stackoverflow.com/a/37462452
    if 'b' in mode:
        buffering = 0

    if filename == STDIN_PIPE_DASH:
        if filename not in kb.cache.content:
            kb.cache.content[filename] = sys.stdin.read()

        return contextlib.closing(io.StringIO(readCachedFileContent(filename)))
    else:
        try:
            return codecs_open(filename, mode, encoding, errors, buffering)
        except IOError:
            errMsg = "there has been a file opening error for filename '%s'. " % filename
            errMsg += "Please check %s permissions on a file " % ("write" if mode and ('w' in mode or 'a' in mode or '+' in mode) else "read")
            errMsg += "and that it's not locked by another process"
            raise SqlmapSystemException(errMsg)

def decodeIntToUnicode(value):
    """