Method hashCode

python/249_Group_Shifted_Strings.py:16–30

(self, string)

        return dic.values()

    def hashCode(self, string):
        if string is None or len(string) == 0:
            return ''
        if len(string) == 1:
            return 'a'
        step = abs(ord(string[0]) - ord('a'))
        if step == 0:
            return string
        key = 'a'
        for ch in string[1:]:
            curr = ord(ch) - step
            if ord(ch) - step < ord('a'):
                curr += 26
            key += chr(curr)
        return key