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Function revoke

core/src/stdlib/pyscript/fs.py:217–258  ·  view source on GitHub ↗

Revoke filesystem access permission and unmount for a given `path` and `id` combination. This removes the stored permission for accessing the user's local filesystem at the specified path and ID. Unlike `unmount()`, which only removes the mount point, `revoke()` also clears the

(path, id="pyscript")

Source from the content-addressed store, hash-verified

215
216
217async def revoke(path, id="pyscript"):
218 """
219 Revoke filesystem access permission and unmount for a given
220 `path` and `id` combination.
221
222 This removes the stored permission for accessing the user's local
223 filesystem at the specified path and ID. Unlike `unmount()`, which only
224 removes the mount point, `revoke()` also clears the permission so the
225 user will be prompted again on next mount.
226
227 ```python
228 from pyscript import fs
229
230
231 await fs.mount("/local", id="my-app")
232 # ... work with files ...
233
234 # Revoke permission (user will be prompted again next time).
235 revoked = await fs.revoke("/local", id="my-app")
236
237 if revoked:
238 print("Permission revoked successfully")
239 ```
240
241 After revoking, the user will need to grant permission again and
242 select a directory when `mount()` is called next time.
243 """
244 mount_key = f"{path}@{id}"
245
246 if RUNNING_IN_WORKER:
247 handler_exists = sync_with_worker.deleteFSHandler(mount_key)
248 else:
249 handler_exists = await _fs.idb.has(mount_key)
250 if handler_exists:
251 handler_exists = await _fs.idb.delete(mount_key)
252
253 if handler_exists:
254 interpreter._module.FS.unmount(path)
255 if path in mounted:
256 del mounted[path]
257
258 return handler_exists

Callers

nothing calls this directly

Calls 2

hasMethod · 0.80
deleteMethod · 0.45

Tested by

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