Method laplace

benchmarks/benchmarks/bench_app.py:34–39

(N, Niter=100, func=num_update, args=())

                        out=u[1:(-1), 1:(-1)])

        def laplace(N, Niter=100, func=num_update, args=()):
            u = np.zeros([N, N], order='C')
            u[0] = 1
            for i in range(Niter):
                func(u, *args)
            return u

        func = {'inplace': num_inplace, 'normal': num_update}[update]