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Function getOutputFileNames

test/fixtures/snapshot/typescript.js:110188–110199  ·  view source on GitHub ↗
(commandLine, inputFileName, ignoreCase)

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110186 }
110187 ts.getAllProjectOutputs = getAllProjectOutputs;
110188 function getOutputFileNames(commandLine, inputFileName, ignoreCase) {
110189 inputFileName = ts.normalizePath(inputFileName);
110190 ts.Debug.assert(ts.contains(commandLine.fileNames, inputFileName), "Expected fileName to be present in command line");
110191 var _a = createAddOutput(), addOutput = _a.addOutput, getOutputs = _a.getOutputs;
110192 if (ts.outFile(commandLine.options)) {
110193 getSingleOutputFileNames(commandLine, addOutput);
110194 }
110195 else {
110196 getOwnOutputFileNames(commandLine, inputFileName, ignoreCase, addOutput);
110197 }
110198 return getOutputs();
110199 }
110200 ts.getOutputFileNames = getOutputFileNames;
110201 /*@internal*/
110202 function getFirstProjectOutput(configFile, ignoreCase) {

Callers

nothing calls this directly

Calls 6

createAddOutputFunction · 0.85
getSingleOutputFileNamesFunction · 0.85
getOwnOutputFileNamesFunction · 0.85
getOutputsFunction · 0.85
assertMethod · 0.80
containsMethod · 0.45

Tested by

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