Function bindObjectDefinePrototypeProperty

test/fixtures/snapshot/typescript.js:47301–47308

(node)

            bindPropertyAssignment(node.left.expression, node.left, /*isPrototypeProperty*/ false, /*containerIsClass*/ true);
        }
        function bindObjectDefinePrototypeProperty(node) {
            var namespaceSymbol = lookupSymbolForPropertyAccess(node.arguments[0].expression);
            if (namespaceSymbol && namespaceSymbol.valueDeclaration) {
                // Ensure the namespace symbol becomes class-like
                addDeclarationToSymbol(namespaceSymbol, namespaceSymbol.valueDeclaration, 32 /* SymbolFlags.Class */);
            }
            bindPotentiallyNewExpandoMemberToNamespace(node, namespaceSymbol, /*isPrototypeProperty*/ true);
        }
        /**
         * For `x.prototype.y = z`, declare a member `y` on `x` if `x` is a function or class, or not declared.
         * Note that jsdoc preceding an ExpressionStatement like `x.prototype.y;` is also treated as a declaration.