(self, nums: List[int])
| 1 | class Solution: |
| 2 | def sortArray(self, nums: List[int]) -> List[int]: |
| 3 | def merge(arr, L, M, R): |
| 4 | left, right = arr[L:M+1], arr[M+1:R+1] |
| 5 | i, j, k = L, 0, 0 |
| 6 | while j < len(left) and k < len(right): |
| 7 | if left[j] <= right[k]: |
| 8 | arr[i] = left[j] |
| 9 | j += 1 |
| 10 | else: |
| 11 | arr[i] = right[k] |
| 12 | k += 1 |
| 13 | i += 1 |
| 14 | while j < len(left): |
| 15 | nums[i] = left[j] |
| 16 | j += 1 |
| 17 | i += 1 |
| 18 | while k < len(right): |
| 19 | nums[i] = right[k] |
| 20 | k += 1 |
| 21 | i += 1 |
| 22 | |
| 23 | def mergeSort(arr, l, r): |
| 24 | if l == r: |
| 25 | return arr |
| 26 | m = (l + r) // 2 |
| 27 | mergeSort(arr, l, m) |
| 28 | mergeSort(arr, m + 1, r) |
| 29 | merge(arr, l, m, r) |
| 30 | return arr |
| 31 | |
| 32 | return mergeSort(nums, 0, len(nums) - 1) |
nothing calls this directly
no test coverage detected