Method exist

python/0079-word-search.py:2–36

(self, board: List[List[str]], word: str)

class Solution:
    def exist(self, board: List[List[str]], word: str) -> bool:
        ROWS, COLS = len(board), len(board[0])
        path = set()

        def dfs(r, c, i):
            if i == len(word):
                return True
            if (
                min(r, c) < 0
                or r >= ROWS
                or c >= COLS
                or word[i] != board[r][c]
                or (r, c) in path
            ):
                return False
            path.add((r, c))
            res = (
                dfs(r + 1, c, i + 1)
                or dfs(r - 1, c, i + 1)
                or dfs(r, c + 1, i + 1)
                or dfs(r, c - 1, i + 1)
            )
            path.remove((r, c))
            return res

        # To prevent TLE,reverse the word if frequency of the first letter is more than the last letter's
        count = sum(map(Counter, board), Counter())
        if count[word[0]] > count[word[-1]]:
            word = word[::-1]
            
        for r in range(ROWS):
            for c in range(COLS):
                if dfs(r, c, 0):
                    return True
        return False

    # O(n * m * 4^n)