Method isPalindrome

java/0131-palindrome-partitioning.java:20–25

(String s, int n)

    }

    public boolean isPalindrome(String s, int n) {
        for (int i = 0; i < n / 2; i++) {
            if (s.charAt(i) != s.charAt(n - i - 1)) return false;
        }
        return true;
    }
}