Function bfs

javascript/0090-subsets-ii.js:44–61

(nums, subsets = [[]])

};

const bfs = (nums, subsets = [[]]) => {
    let levels = subsets.length - 1;

    for (let i = 0; i < nums.length; i++) {
        const isPrevDuplicate = 0 < i && nums[i - 1] === nums[i];
        const start = isPrevDuplicate ? levels + 1 : 0;

        levels = subsets.length - 1;

        for (let level = start; level < levels + 1; level++) {
            const nextLevel = [...subsets[level], nums[i]];

            subsets.push(nextLevel);
        }
    }

    return subsets;
};