* Return true if we have the source content for every source in the source * map, false otherwise.
()
| 177 | * map, false otherwise. |
| 178 | */ |
| 179 | hasContentsOfAllSources(): boolean; |
| 180 | |
| 181 | /** |
| 182 | * Returns the original source content. The only argument is the url of the |
no outgoing calls
no test coverage detected