Method hasUses

source/python.js:12772–12779

()

                return this._outputs[i];
            }
            hasUses() {
                for (const o of this.outputs()) {
                    if (o.uses().length > 0) {
                        return true;
                    }
                }
                return false;
            }
            blocks() {
                return this._blocks;
            }