Function smooth

rl2/a3c/main.py:41–48

(x)

def smooth(x):
  # last 100
  n = len(x)
  y = np.zeros(n)
  for i in range(n):
    start = max(0, i - 99)
    y[i] = float(x[start:(i+1)].sum()) / (i - start + 1)
  return y


# Set the number of workers