Function filter_ns

IPython/utils/wildcard.py:75–87

Filter a namespace dictionary by name pattern and item type.

(ns, name_pattern="*", type_pattern="all", ignore_case=True,
            show_all=True)

    return ns

def filter_ns(ns, name_pattern="*", type_pattern="all", ignore_case=True,
            show_all=True):
    """Filter a namespace dictionary by name pattern and item type."""
    pattern = name_pattern.replace("*",".*").replace("?",".")
    if ignore_case:
        reg = re.compile(pattern+"$", re.I)
    else:
        reg = re.compile(pattern+"$")

    # Check each one matches regex; shouldn't be hidden; of correct type.
    return dict((key,obj) for key, obj in ns.items() if reg.match(key) \
                                            and show_hidden(key, show_all) \
                                            and is_type(obj, type_pattern) )

def list_namespace(namespace, type_pattern, filter, ignore_case=False, show_all=False):
    """Return dictionary of all objects in a namespace dictionary that match