Least common multiple input: two positive integer 'number1' and 'number2' returns the least common multiple of 'number1' and 'number2'
(number1, number2)
| 364 | |
| 365 | |
| 366 | def kgV(number1, number2): |
| 367 | """ |
| 368 | Least common multiple |
| 369 | input: two positive integer 'number1' and 'number2' |
| 370 | returns the least common multiple of 'number1' and 'number2' |
| 371 | """ |
| 372 | |
| 373 | # precondition |
| 374 | assert ( |
| 375 | isinstance(number1, int) |
| 376 | and isinstance(number2, int) |
| 377 | and (number1 >= 1) |
| 378 | and (number2 >= 1) |
| 379 | ), "'number1' and 'number2' must been positive integer." |
| 380 | |
| 381 | ans = 1 # actual answer that will be return. |
| 382 | |
| 383 | # for kgV (x,1) |
| 384 | if number1 > 1 and number2 > 1: |
| 385 | # builds the prime factorization of 'number1' and 'number2' |
| 386 | primeFac1 = primeFactorization(number1) |
| 387 | primeFac2 = primeFactorization(number2) |
| 388 | |
| 389 | elif number1 == 1 or number2 == 1: |
| 390 | primeFac1 = [] |
| 391 | primeFac2 = [] |
| 392 | ans = max(number1, number2) |
| 393 | |
| 394 | count1 = 0 |
| 395 | count2 = 0 |
| 396 | |
| 397 | done = [] # captured numbers int both 'primeFac1' and 'primeFac2' |
| 398 | |
| 399 | # iterates through primeFac1 |
| 400 | for n in primeFac1: |
| 401 | if n not in done: |
| 402 | if n in primeFac2: |
| 403 | count1 = primeFac1.count(n) |
| 404 | count2 = primeFac2.count(n) |
| 405 | |
| 406 | for i in range(max(count1, count2)): |
| 407 | ans *= n |
| 408 | |
| 409 | else: |
| 410 | count1 = primeFac1.count(n) |
| 411 | |
| 412 | for i in range(count1): |
| 413 | ans *= n |
| 414 | |
| 415 | done.append(n) |
| 416 | |
| 417 | # iterates through primeFac2 |
| 418 | for n in primeFac2: |
| 419 | if n not in done: |
| 420 | count2 = primeFac2.count(n) |
| 421 | |
| 422 | for i in range(count2): |
| 423 | ans *= n |
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