Function intersection

packages/effect-app/src/Set.ts:63–66

(E: Equivalence.Equivalence<A>)

 * The set of elements which are in both the first and second set
 */
export function intersection<A>(E: Equivalence.Equivalence<A>): (r: Set<A>) => (l: Set<A>) => Set<A> {
  const i = intersection_(E)
  return (x) => (y) => i(x, y)
}

/**
 * Convert a mutable set to a readonly one