Return vector perpendicular to vectors. >>> v = vector_product([2, 0, 0], [0, 3, 0]) >>> numpy.allclose(v, [0, 0, 6]) True >>> v0 = [[2, 0, 0, 2], [0, 2, 0, 2], [0, 0, 2, 2]] >>> v1 = [[3], [0], [0]] >>> v = vector_product(v0, v1) >>> numpy.allclose(v, [[0, 0, 0, 0], [0,
(v0, v1, axis=0)
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