(fiber)
| 5702 | return MOUNTED;}// If we didn't hit the root, that means that we're in an disconnected tree |
| 5703 | // that has been unmounted. |
| 5704 | return UNMOUNTED;}var isFiberMounted=function isFiberMounted(fiber){return isFiberMountedImpl(fiber)===MOUNTED;};var isMounted=function isMounted(component){{var owner=ReactCurrentOwner.current;if(owner!==null&&owner.tag===ClassComponent){var ownerFiber=owner;var instance=ownerFiber.stateNode;warning$1(instance._warnedAboutRefsInRender,'%s is accessing isMounted inside its render() function. '+'render() should be a pure function of props and state. It should '+'never access something that requires stale data from the previous '+'render, such as refs. Move this logic to componentDidMount and '+'componentDidUpdate instead.',getComponentName_1(ownerFiber)||'A component');instance._warnedAboutRefsInRender=true;}}var fiber=ReactInstanceMap_1.get(component);if(!fiber){return false;}return isFiberMountedImpl(fiber)===MOUNTED;};function assertIsMounted(fiber){!(isFiberMountedImpl(fiber)===MOUNTED)?invariant(false,'Unable to find node on an unmounted component.'):void 0;}function findCurrentFiberUsingSlowPath(fiber){var alternate=fiber.alternate;if(!alternate){// If there is no alternate, then we only need to check if it is mounted. |
| 5705 | var state=isFiberMountedImpl(fiber);!(state!==UNMOUNTED)?invariant(false,'Unable to find node on an unmounted component.'):void 0;if(state===MOUNTING){return null;}return fiber;}// If we have two possible branches, we'll walk backwards up to the root |
| 5706 | // to see what path the root points to. On the way we may hit one of the |
| 5707 | // special cases and we'll deal with them. |
| 5708 | var a=fiber;var b=alternate;while(true){var parentA=a['return'];var parentB=parentA?parentA.alternate:null;if(!parentA||!parentB){// We're at the root. |
| 5709 | break;}// If both copies of the parent fiber point to the same child, we can |
| 5710 | // assume that the child is current. This happens when we bailout on low |
| 5711 | // priority: the bailed out fiber's child reuses the current child. |
| 5712 | if(parentA.child===parentB.child){var child=parentA.child;while(child){if(child===a){// We've determined that A is the current branch. |
| 5713 | assertIsMounted(parentA);return fiber;}if(child===b){// We've determined that B is the current branch. |
| 5714 | assertIsMounted(parentA);return alternate;}child=child.sibling;}// We should never have an alternate for any mounting node. So the only |
| 5715 | // way this could possibly happen is if this was unmounted, if at all. |
| 5716 | invariant(false,'Unable to find node on an unmounted component.');}if(a['return']!==b['return']){// The return pointer of A and the return pointer of B point to different |
| 5717 | // fibers. We assume that return pointers never criss-cross, so A must |
| 5718 | // belong to the child set of A.return, and B must belong to the child |
| 5719 | // set of B.return. |
| 5720 | a=parentA;b=parentB;}else{// The return pointers point to the same fiber. We'll have to use the |
| 5721 | // default, slow path: scan the child sets of each parent alternate to see |
| 5722 | // which child belongs to which set. |
| 5723 | // |
| 5724 | // Search parent A's child set |
| 5725 | var didFindChild=false;var _child=parentA.child;while(_child){if(_child===a){didFindChild=true;a=parentA;b=parentB;break;}if(_child===b){didFindChild=true;b=parentA;a=parentB;break;}_child=_child.sibling;}if(!didFindChild){// Search parent B's child set |
| 5726 | _child=parentB.child;while(_child){if(_child===a){didFindChild=true;a=parentB;b=parentA;break;}if(_child===b){didFindChild=true;b=parentB;a=parentA;break;}_child=_child.sibling;}!didFindChild?invariant(false,'Child was not found in either parent set. This indicates a bug in React related to the return pointer. Please file an issue.'):void 0;}}!(a.alternate===b)?invariant(false,'Return fibers should always be each others\' alternates. This error is likely caused by a bug in React. Please file an issue.'):void 0;}// If the root is not a host container, we're in a disconnected tree. I.e. |
| 5727 | // unmounted. |
| 5728 | !(a.tag===HostRoot$1)?invariant(false,'Unable to find node on an unmounted component.'):void 0;if(a.stateNode.current===a){// We've determined that A is the current branch. |
| 5729 | return fiber;}// Otherwise B has to be current branch. |
| 5730 | return alternate;}var findCurrentFiberUsingSlowPath_1=findCurrentFiberUsingSlowPath;var findCurrentHostFiber=function findCurrentHostFiber(parent){var currentParent=findCurrentFiberUsingSlowPath(parent);if(!currentParent){return null;}// Next we'll drill down this component to find the first HostComponent/Text. |
| 5731 | var node=currentParent;while(true){if(node.tag===HostComponent$1||node.tag===HostText$1){return node;}else if(node.child){node.child['return']=node;node=node.child;continue;}if(node===currentParent){return null;}while(!node.sibling){if(!node['return']||node['return']===currentParent){return null;}node=node['return'];}node.sibling['return']=node['return'];node=node.sibling;}// Flow needs the return null here, but ESLint complains about it. |
| 5732 | // eslint-disable-next-line no-unreachable |
| 5733 | return null;};var findCurrentHostFiberWithNoPortals=function findCurrentHostFiberWithNoPortals(parent){var currentParent=findCurrentFiberUsingSlowPath(parent);if(!currentParent){return null;}// Next we'll drill down this component to find the first HostComponent/Text. |
no test coverage detected