Method openFile

test/e2e/models/CodeServer.ts:406–410

* Open a file by using menus.

(file: string)

   * Open a file by using menus.
   */
  async openFile(file: string) {
    await this.navigateMenus(["File", "Open File..."])
    await this.navigateQuickInput([path.basename(file)])
    await this.waitForTab(file)
  }

  /**
   * Open a file through an external command.