function should print the topView of the binary tree
| 25 | // function should print the topView of |
| 26 | // the binary tree |
| 27 | void topview(Node *root) |
| 28 | { |
| 29 | if (root == NULL) |
| 30 | return; |
| 31 | queue<Node *> q; |
| 32 | map<int, int> m; |
| 33 | int hd = 0; |
| 34 | root->hd = hd; |
| 35 | |
| 36 | // push node and horizontal distance to queue |
| 37 | q.push(root); |
| 38 | |
| 39 | cout << "The top view of the tree is : \n"; |
| 40 | |
| 41 | while (q.size()) |
| 42 | { |
| 43 | hd = root->hd; |
| 44 | |
| 45 | // count function returns 1 if the container |
| 46 | // contains an element whose key is equivalent |
| 47 | // to hd, or returns zero otherwise. |
| 48 | if (m.count(hd) == 0) |
| 49 | m[hd] = root->data; |
| 50 | if (root->left) |
| 51 | { |
| 52 | root->left->hd = hd - 1; |
| 53 | q.push(root->left); |
| 54 | } |
| 55 | if (root->right) |
| 56 | { |
| 57 | root->right->hd = hd + 1; |
| 58 | q.push(root->right); |
| 59 | } |
| 60 | q.pop(); |
| 61 | root = q.front(); |
| 62 | } |
| 63 | |
| 64 | for (auto i = m.begin(); i != m.end(); i++) |
| 65 | { |
| 66 | cout << i->second << " "; |
| 67 | } |
| 68 | } |
| 69 | |
| 70 | |
| 71 | int main() |