Method sortByNum

buffer.go:300–336

sortByNum sorts column by number format with optimized numeric conversion

(colIndex int, rev bool)

// sortByNum sorts column by number format with optimized numeric conversion
func (b *Buffer) sortByNum(colIndex int, rev bool) {
	hasHeader := I2B(b.rowFreeze)
	dataRows := b.cont
	if hasHeader {
		dataRows = b.cont[1:]
	}

	// Create index-value pairs to sort
	type numRow struct {
		row []string
		num float64
	}

	pairs := make([]numRow, len(dataRows))
	for i := range dataRows {
		pairs[i] = numRow{
			row: dataRows[i],
			num: parseNumericValueFast(dataRows[i][colIndex]),
		}
	}

	// Sort the pairs
	if rev {
		sort.SliceStable(pairs, func(i, j int) bool {
			return pairs[i].num > pairs[j].num
		})
	} else {
		sort.SliceStable(pairs, func(i, j int) bool {
			return pairs[i].num < pairs[j].num
		})
	}

	// Copy back sorted rows
	for i := range pairs {
		dataRows[i] = pairs[i].row
	}
}

// sortByDate sorts column by date format with optimized date parsing
func (b *Buffer) sortByDate(colIndex int, rev bool) {