Function count_syllables

pattern/metrics.py:306–313

(word, vowels="aeiouy")

        0.30-0.50 (difficult) => 0.60-0.70 (standard) => 0.90-1.00 (very easy).
    """
    def count_syllables(word, vowels="aeiouy"):
        n = 0
        p = False # True if the previous character was a vowel.
        for ch in word.endswith("e") and word[:-1] or word:
            v = ch in vowels
            n += int(v and not p)
            p = v
        return n
    if len(string) <  3:
        return 1.0
    string = string.strip()