Method typeFromName

libchigraph/src/LangModule.cpp:883–920

the lang module just has the basic llvm types.

// the lang module just has the basic llvm types.
DataType LangModule::typeFromName(boost::string_view name) {
	using namespace std::string_literals;

	llvm::Type* ty;

	auto err = llvm::SMDiagnostic();
#if LLVM_VERSION_LESS_EQUAL(3, 8)
	// just parse the type
	auto IR = "@G = external global "s + name.to_string();

	auto tmpModule = llvm::
#if LLVM_VERSION_LESS_EQUAL(3, 5)
	    ParseAssemblyString(IR.c_str(), new llvm::Module("tmp", context().llvmContext()), err,
	                        context().llvmContext());
#else
	    parseAssemblyString(IR, err, context().llvmContext());
#endif

	if (!tmpModule) { return nullptr; }

	ty = tmpModule->getNamedValue("G")->getType()->getContainedType(0);
#else
	{
		llvm::Module tMod("tmp", context().llvmContext());
		ty = llvm::parseType(name.to_string(), err, tMod, nullptr);
	}
#endif

	// get debug type
	auto iter = mDebugTypes.find(name.to_string());
	if (iter == mDebugTypes.end()) { return {}; }

#if LLVM_VERSION_LESS_EQUAL(3, 5)
	delete tmpModule;
#endif

	return DataType{this, name.to_string(), ty, iter->second};
}

Result LangModule::addForwardDeclarations(llvm::Module&) const { return {}; }