| 1 | class Solution { |
| 2 | public: |
| 3 | vector<int> merge(vector<int> &A, vector<int>& B){ |
| 4 | int sizeA=A.size(); |
| 5 | int sizeB=B.size(); |
| 6 | int i=0; |
| 7 | int j=0; |
| 8 | vector<int> ans; |
| 9 | |
| 10 | //Compare and fill ans vector |
| 11 | while (i<sizeA && j<sizeB){ |
| 12 | if(A[i]<B[j]){ |
| 13 | ans.push_back(A[i]); |
| 14 | i=i+1; |
| 15 | } else{ |
| 16 | ans.push_back(B[j]); |
| 17 | j=j+1; |
| 18 | } |
| 19 | } |
| 20 | |
| 21 | //Add remaining elements from A |
| 22 | while(i<sizeA){ |
| 23 | ans.push_back(A[i]); |
| 24 | i=i+1; |
| 25 | } |
| 26 | |
| 27 | //Add remaining elements from B |
| 28 | while(j<sizeB){ |
| 29 | ans.push_back(B[j]); |
| 30 | j=j+1; |
| 31 | } |
| 32 | |
| 33 | return ans; |
| 34 | |
| 35 | } |
| 36 | |
| 37 | vector<int> mergeSort(vector<int>& nums,int start, int end) { |
| 38 | //Base Case |
| 39 | if (start>end){ |
| 40 | return {}; |
| 41 | } |
| 42 | if (start==end){ |
| 43 | return {nums[start]}; |
| 44 | } |
| 45 | |
| 46 | //Calculate Mid |
| 47 | int mid= start+(end-start)/2; |
| 48 | |
| 49 | //MergeSortCall |
| 50 | vector<int> A = mergeSort(nums,start,mid); |
| 51 | vector<int> B = mergeSort(nums,mid+1,end); |
| 52 | |
| 53 | //MergeCall |
| 54 | return merge(A,B); |
| 55 | } |
| 56 | |
| 57 | vector<int> sortArray(vector<int>& nums) { |
| 58 | int n=nums.size(); |
| 59 | return mergeSort(nums,0,n-1); |
| 60 | } |
nothing calls this directly
no outgoing calls
no test coverage detected