Copy the input expression with a brand new set of identifiers.
(ast.Expr)
| 197 | type ExprHelper interface { |
| 198 | // Copy the input expression with a brand new set of identifiers. |
| 199 | Copy(ast.Expr) ast.Expr |
| 200 | |
| 201 | // Literal creates an Expr value for a scalar literal value. |
| 202 | NewLiteral(value ref.Val) ast.Expr |
no outgoing calls