Method left_sibling_branch_level

cranelift/bforest/src/path.rs:605–607

Find the level where the left sibling to the current node at `level` branches off.

(&self, level: usize)

    /// Find the level where the left sibling to the current node at `level` branches off.
    fn left_sibling_branch_level(&self, level: usize) -> Option<usize> {
        self.entry[0..level].iter().rposition(|&e| e != 0)
    }

    /// Get the right sibling node to the current node at `level`.
    /// Also return the critical key between the current node and the right sibling.