Default Arguments in Rust

Enables default arguments in rust by macro in zero cost. Just wrap function with default_args! and macro with name of function would be automatically generated to be used with default argument. See below for usage

use default_args::default_args;

// this would make a macro named `foo`
// and original function named `foo_`
default_args! {
    fn foo(important_arg: u32, optional: u32 = 100) -> String {
        format!("{}, {}", important_arg, optional)
    }
}

// in other codes ...
assert_eq!(foo!(1), "1, 100"); // foo(1, 100)
assert_eq!(foo!(1, 3), "1, 3"); // foo(1, 3)
assert_eq!(foo!(1, optional = 10), "1, 10"); // foo(1, 10)

// let's make another one
default_args! {
    #[inline]
    pub async unsafe extern "C" fn bar<S1, S2, S3>(a: S1, b: S2 = "b", c: S3 = "c") -> String
    where
        S1: AsRef<str>,
        S2: AsRef<str>,
        S3: AsRef<str>,
    {
        format!("{}, {}, {}", a.as_ref(), b.as_ref(), c.as_ref())
    }
    // that was long signature!
}

// in other codes ...
assert_eq!(unsafe { bar!("a") }.await, "a, b, c");
assert_eq!(unsafe { bar!("a", "d") }.await, "a, d, c");
// you can even mix named & unnamed argument in optional arguments
assert_eq!(unsafe { bar!("a", "d", c = "e") }.await, "a, d, e");
assert_eq!(unsafe { bar!("a", c = "e") }.await, "a, b, e");

See examples for more information.

More Features

Export

Add export in the front of the function and the macro would be exported. (add pub to export function with macro)

default_args! {
    export pub fn foo() {}
}

Above macro will expand as below

pub fn foo_() {}

#[macro_export]
macro_rules! foo { () => {}; }

Path of function

Macro just call the function in name, so you should import both macro and the function to use it. By writing the path of this function, you can just only import the macro. (path should start with crate)

#[macro_use]
pub mod foo {
    default_args! {
        pub fn crate::foo::bar() {}
    }
}

// then it would create `bar!()`
bar!();

Above macro would expand as below

pub mod foo {
    pub fn bar_() {}

    macro_rules! bar_ {
        () => {
            $crate::foo::bar_()
        };
    }
}

Why do we have to write module?

std::module_path! can resolve the module path of the function where it is declared. However, it can be resolved in runtime, not compile-time. I couldn't find a way to get module path in compile-time.

License

MIT License