Find the last character present in the specified string. Search from `pos` backwards for the first character in this string that is equal to any of the characters of `sv`. If `pos` is equal to @ref npos (the default), search from the last character. @par Complexity Linear in @ref size() `+ sv.size()`. @par Exception Safety No-throw guarant
| 1937 | @param pos The index to start searching at. |
| 1938 | */ |
| 1939 | std::size_t |
| 1940 | find_last_of( |
| 1941 | string_view sv, |
| 1942 | std::size_t pos = npos) const noexcept |
| 1943 | { |
| 1944 | return subview().find_last_of(sv, pos); |
| 1945 | } |
| 1946 | |
| 1947 | /** Find the last character missing from the specified string. |
| 1948 |