Method get_child

v2/test/tree.py:64–72

If the given TreeNode directory NODE contains a child named NAME, return the child; else, return None.

(self, name)

            newchild.path = os.path.join(self.path, newchild.name)

    def get_child(self, name):
        """
          If the given TreeNode directory NODE contains a child named NAME,
        return the child; else, return None.

        """
        for n in self.children:
            if n.name == name:
                return n

    def is_file(self):
        return self.children is None