返回不存在另一个PCollection中的元素,相当于做容器减法 Args: other (PCollection): 作为减数的PCollection Returns: PCollection: 表示减法结果的PCollection >>> a = _pipeline.parallelize([1, 2, 3, 3, 4]) >>> b = _pipeline.parallelize([1, 2, 5]) >>> a.subtract(b).ge
(self, other)
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no outgoing calls