返回与另一个PCollection的交集 Args: other (PCollection): 另一个PCollection Returns: PCollection: 表示交集的PCollection >>> a = _pipeline.parallelize([1, 1, 2, 3]) >>> b = _pipeline.parallelize([1, 1, 2, 2, 5]) >>> a.intersection(b).get()
(self, other, output_duplicated = False)
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