Function LexRegex

lex/lexer.go:1106–1145

lex a regex: first character must be a / ^stats\./i .*/ ^stats.*/

(l *Lexer)

//  /^stats.*/
//
func LexRegex(l *Lexer) StateFn {

	l.SkipWhiteSpaces()
	if l.IsEnd() {
		return l.errorToken("expected value but got EOF")
	}

	rune := l.Next()
	if rune != '/' {
		return nil
	}

	previousEscaped := rune == '/'
	// scan looking for ending character = /
	for rune = l.Next(); ; rune = l.Next() {
		if rune == eof {
			return l.errorToken("expected value but got EOF")
		}
		//u.Debugf("LexRegex rune=%v  end?%v  prevEscape?%v", string(rune), rune == eof, previousEscaped)
		if rune == '/' && !previousEscaped {
			// now that we have found what appears to be end, lets see if it
			// has a modifier - the i/g at end of    /^stats\./i
			for rune = l.Next(); ; rune = l.Next() {
				//u.Debugf("LexRegex rune=%v  end?%v  prevEscape?%v", string(rune), rune == eof, previousEscaped)
				if rune == eof {
					l.Emit(TokenRegex)
					return nil
					//return l.errorToken("expected value but got EOF")
				}
				if isWhiteSpace(rune) {
					l.backup()
					l.Emit(TokenRegex)
					return nil
				}
			}
		}

		previousEscaped = rune == '/'
	}
}

// look for either an Expression or Identity
//