| 2 | package Arrays; |
| 3 | |
| 4 | public class MaxSubarraySum { |
| 5 | //bruteforce |
| 6 | public static void maxSubarraySum1(int arr[]) { |
| 7 | int largestSum = Integer.MIN_VALUE; |
| 8 | |
| 9 | for(int i=0; i<arr.length; i++) { |
| 10 | for(int j=i+1; j<arr.length; j++) { |
| 11 | int currSum = 0; |
| 12 | for(int k=i; k<=j; k++) { |
| 13 | currSum += arr[k]; |
| 14 | } |
| 15 | largestSum = Math.max(largestSum, currSum); |
| 16 | } |
| 17 | } |
| 18 | |
| 19 | System.out.println("max subarray sum is : " + largestSum); |
| 20 | } |
| 21 | |
| 22 | //optimization1 : Prefix Sum array |
| 23 | public static void maxSubarraySum2(int arr[]) { |
| 24 | int maxSum = Integer.MIN_VALUE; |
| 25 | |
| 26 | int prefix[] = new int[arr.length]; |
| 27 | prefix[0] = arr[0]; |
| 28 | for(int i=1; i<arr.length; i++) { |
| 29 | prefix[i] = prefix[i-1] + arr[i]; |
| 30 | } |
| 31 | |
| 32 | for(int i=0; i<arr.length; i++) { |
| 33 | for(int j=i+1; j<arr.length; j++) { |
| 34 | int currSum = i==0 ? prefix[j] : prefix[j] - prefix[i-1]; |
| 35 | maxSum = Math.max(maxSum, currSum); |
| 36 | } |
| 37 | } |
| 38 | |
| 39 | System.out.println("max subarray sum is : " + maxSum); |
| 40 | } |
| 41 | |
| 42 | //Kadane's Algorithm |
| 43 | public static void maxSubarraySum3(int arr[]) { |
| 44 | int cs = 0; |
| 45 | int ms = 0; |
| 46 | |
| 47 | for(int i=0; i<arr.length; i++) { |
| 48 | cs = cs + arr[i]; |
| 49 | if(cs < 0) { |
| 50 | cs = 0; |
| 51 | } |
| 52 | ms = Math.max(ms, cs); |
| 53 | } |
| 54 | |
| 55 | System.out.println("max subarray sum is : " + ms); |
| 56 | } |
| 57 | public static void main(String args[]) { |
| 58 | int arr[] = {1, -2, 6, -1, 3}; |
| 59 | maxSubarraySum1(arr); |
| 60 | maxSubarraySum2(arr); |
| 61 | maxSubarraySum3(arr); |
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