Find position at the matching start of current expression. This is almost the reverse of FindEndOfExpressionInLine, but note that the input position and returned position differs by 1. Args: line: a CleansedLines line. endpos: start searching at this position. stack: nesting stac
(line, endpos, stack)
| 1644 | |
| 1645 | |
| 1646 | def FindStartOfExpressionInLine(line, endpos, stack): |
| 1647 | """Find position at the matching start of current expression. |
| 1648 | |
| 1649 | This is almost the reverse of FindEndOfExpressionInLine, but note |
| 1650 | that the input position and returned position differs by 1. |
| 1651 | |
| 1652 | Args: |
| 1653 | line: a CleansedLines line. |
| 1654 | endpos: start searching at this position. |
| 1655 | stack: nesting stack at endpos. |
| 1656 | |
| 1657 | Returns: |
| 1658 | On finding matching start: (index at matching start, None) |
| 1659 | On finding an unclosed expression: (-1, None) |
| 1660 | Otherwise: (-1, new stack at beginning of this line) |
| 1661 | """ |
| 1662 | i = endpos |
| 1663 | while i >= 0: |
| 1664 | char = line[i] |
| 1665 | if char in ')]}': |
| 1666 | # Found end of expression, push to expression stack |
| 1667 | stack.append(char) |
| 1668 | elif char == '>': |
| 1669 | # Found potential end of template argument list. |
| 1670 | # |
| 1671 | # Ignore it if it's a "->" or ">=" or "operator>" |
| 1672 | if (i > 0 and |
| 1673 | (line[i - 1] == '-' or |
| 1674 | Match(r'\s>=\s', line[i - 1:]) or |
| 1675 | Search(r'\boperator\s*$', line[0:i]))): |
| 1676 | i -= 1 |
| 1677 | else: |
| 1678 | stack.append('>') |
| 1679 | elif char == '<': |
| 1680 | # Found potential start of template argument list |
| 1681 | if i > 0 and line[i - 1] == '<': |
| 1682 | # Left shift operator |
| 1683 | i -= 1 |
| 1684 | else: |
| 1685 | # If there is a matching '>', we can pop the expression stack. |
| 1686 | # Otherwise, ignore this '<' since it must be an operator. |
| 1687 | if stack and stack[-1] == '>': |
| 1688 | stack.pop() |
| 1689 | if not stack: |
| 1690 | return (i, None) |
| 1691 | elif char in '([{': |
| 1692 | # Found start of expression. |
| 1693 | # |
| 1694 | # If there are any unmatched '>' on the stack, they must be |
| 1695 | # operators. Remove those. |
| 1696 | while stack and stack[-1] == '>': |
| 1697 | stack.pop() |
| 1698 | if not stack: |
| 1699 | return (-1, None) |
| 1700 | if ((char == '(' and stack[-1] == ')') or |
| 1701 | (char == '[' and stack[-1] == ']') or |
| 1702 | (char == '{' and stack[-1] == '}')): |
| 1703 | stack.pop() |
no test coverage detected