Coalesces the vector of ranges provided and modifies `result` to contain the solution. The algorithm first sorts all the individual intervals so that we can iterate over them sequentially. The algorithm does a single pass, after the sort, and builds up the solution in place. It then modifies the `result` with as few steps as possible. The expensive part of this operation is modification of the pro
| 179 | // expensive part of this operation is modification of the protobuf, which is |
| 180 | // why we prefer to build up the solution in a temporary vector. |
| 181 | void coalesce(Value::Ranges* result, vector<Range> ranges) |
| 182 | { |
| 183 | // Exit early if empty. |
| 184 | if (ranges.empty()) { |
| 185 | result->clear_range(); |
| 186 | return; |
| 187 | } |
| 188 | |
| 189 | std::sort( |
| 190 | ranges.begin(), |
| 191 | ranges.end(), |
| 192 | [](const Range& left, const Range& right) { |
| 193 | return std::tie(left.start, left.end) < |
| 194 | std::tie(right.start, right.end); |
| 195 | }); |
| 196 | |
| 197 | // We build up initial state of the current range. |
| 198 | CHECK(!ranges.empty()); |
| 199 | int count = 1; |
| 200 | Range current = ranges.front(); |
| 201 | |
| 202 | // In a single pass, we compute the size of the end result, as well as modify |
| 203 | // in place the intermediate data structure to build up result as we |
| 204 | // solve it. |
| 205 | foreach (const Range& range, ranges) { |
| 206 | // Skip if this range is equivalent to the current range. |
| 207 | if (range.start == current.start && range.end == current.end) { |
| 208 | continue; |
| 209 | } |
| 210 | |
| 211 | // If the current range just needs to be extended on the right. |
| 212 | if (range.start == current.start && range.end > current.end) { |
| 213 | current.end = range.end; |
| 214 | } else if (range.start > current.start) { |
| 215 | // If we are starting farther ahead, then there are 2 cases: |
| 216 | if (range.start <= current.end + 1) { |
| 217 | // 1. Ranges are overlapping and we can merge them. |
| 218 | current.end = max(current.end, range.end); |
| 219 | } else { |
| 220 | // 2. No overlap and we are adding a new range. |
| 221 | ranges[count - 1] = current; |
| 222 | ++count; |
| 223 | current = range; |
| 224 | } |
| 225 | } |
| 226 | } |
| 227 | |
| 228 | // Record the state of the last range into of ranges vector. |
| 229 | ranges[count - 1] = current; |
| 230 | |
| 231 | CHECK(count <= static_cast<int>(ranges.size())); |
| 232 | |
| 233 | // Shrink result if it is too large by deleting trailing subrange. |
| 234 | if (count < result->range_size()) { |
| 235 | result->mutable_range()->DeleteSubrange( |
| 236 | count, result->range_size() - count); |
| 237 | } |
| 238 |
no test coverage detected