Method max

output/java_guava/1.4.16/Ordering.java:603–611

Returns the greatest of the specified values according to this ordering. If there are multiple greatest values, the first of those is returned. The iterator will be left exhausted: its hasNext() method will return false. @param iterator the iterator whose maximum element is to be de

(Iterator<E> iterator)

   */

  @CanIgnoreReturnValue // TODO(kak): Consider removing this
  public <E extends T> E max(Iterator<E> iterator) {
    // let this throw NoSuchElementException as necessary
    E maxSoFar = iterator.next();
    while (iterator.hasNext()) {
      maxSoFar = max(maxSoFar, iterator.next());
    }
    return maxSoFar;
  }

  /**
   * Returns the greatest of the specified values according to this ordering. If