| 1 | package videocode; |
| 2 | |
| 3 | public class Code05_MaxSubArraySum { |
| 4 | |
| 5 | public static int maxSubArraySum1(int[] arr) { |
| 6 | if (arr == null || arr.length == 0) { |
| 7 | return 0; |
| 8 | } |
| 9 | int N = arr.length; |
| 10 | int ans = Integer.MIN_VALUE; |
| 11 | for (int L = 0; L < N; L++) { |
| 12 | for (int R = L; R < N; R++) { |
| 13 | // arr[L..R] |
| 14 | int sum = 0; |
| 15 | for (int i = L; i <= R; i++) { |
| 16 | sum += arr[i]; |
| 17 | } |
| 18 | ans = Math.max(ans, sum); |
| 19 | } |
| 20 | } |
| 21 | return ans; |
| 22 | } |
| 23 | |
| 24 | public static int maxSubArraySum2(int[] arr) { |
| 25 | if (arr == null || arr.length == 0) { |
| 26 | return 0; |
| 27 | } |
| 28 | int N = arr.length; |
| 29 | // dp[i] : 子数组必须以arr[i]结尾的时候,子数组的最大累加和是多少? |
| 30 | int[] dp = new int[N]; |
| 31 | dp[0] = arr[0]; // 0..0 |
| 32 | int ans = arr[0]; |
| 33 | // dp[1] -> dp[0] |
| 34 | // dp[2] -> dp[1] |
| 35 | // dp[3] -> dp[2] |
| 36 | // dp[4] -> dp[3] |
| 37 | // dp[i] => dp[i-1] |
| 38 | for (int i = 1; i < N; i++) { |
| 39 | dp[i] = Math.max(arr[i], arr[i] + dp[i - 1]); |
| 40 | ans = Math.max(ans, dp[i]); |
| 41 | } |
| 42 | return ans; |
| 43 | } |
| 44 | |
| 45 | public static int maxSubArraySum3(int[] arr) { |
| 46 | if (arr == null || arr.length == 0) { |
| 47 | return 0; |
| 48 | } |
| 49 | int N = arr.length; |
| 50 | // pre -> dp[0] |
| 51 | int pre = arr[0]; |
| 52 | int ans = arr[0]; |
| 53 | for (int i = 1; i < N; i++) { |
| 54 | // dp[3] dp[2] |
| 55 | pre = Math.max(arr[i], arr[i] + pre); |
| 56 | ans = Math.max(ans, pre); |
| 57 | } |
| 58 | return ans; |
| 59 | } |
| 60 |
nothing calls this directly
no outgoing calls
no test coverage detected