Function nolocks_localtime

lib_acl/src/stdlib/string/acl_localtime.c:75–128

}

static void nolocks_localtime(struct tm *tmp, time_t t, time_t tz, int dst)
{
	const time_t secs_min  = 60;
	const time_t secs_hour = 3600;
	const time_t secs_day  = 3600*24;

	t -= tz;                            /* Adjust for timezone. */
	t += 3600 * dst;                   /* Adjust for daylight time. */
	time_t days = t / secs_day;         /* Days passed since epoch. */
	time_t seconds = t % secs_day;      /* Remaining seconds. */

	tmp->tm_isdst = dst;
	tmp->tm_hour = (int) (seconds / secs_hour);
	tmp->tm_min = (seconds % secs_hour) / secs_min;
	tmp->tm_sec = (seconds % secs_hour) % secs_min;

	/* 1/1/1970 was a Thursday, that is, day 4 from the POV of the tm
	 * structure where sunday = 0, so to calculate the day of the week
	 * we have to add 4 
	 * and take the modulo by 7.
	 */
	tmp->tm_wday = (days + 4) % 7;

	/* Calculate the current year. */
	tmp->tm_year = 1970;
	while(1) {
		/* Leap years have one day more. */
		time_t days_this_year = 365 + is_leap_year(tmp->tm_year);
		if (days_this_year > days) {
			break;
		}
		days -= days_this_year;
		tmp->tm_year++;
	}

	tmp->tm_yday = (int) days;  /* Number of day of the current year. */

	/* We need to calculate in which month and day of the month we are.
	 * To do so we need to skip days according to how many days there are
	 * in each month, and adjust for the leap year that has one more day
	 * in February.
	 */
	int mdays[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
	mdays[1] += is_leap_year(tmp->tm_year);

	tmp->tm_mon = 0;
	while(days >= mdays[tmp->tm_mon]) {
		days -= mdays[tmp->tm_mon];
		tmp->tm_mon++;
	}

	tmp->tm_mday = (int) days + 1;  /* Add 1 since our 'days' is zero-based. */
	tmp->tm_year -= 1900;     /* Surprisingly tm_year is year-1900. */
}

static int daylight_active;