| 9 | } |
| 10 | |
| 11 | void itos(char *numStr, uint32 num, uint32 mod) |
| 12 | { |
| 13 | |
| 14 | // 只能转换2~26进制的整数 |
| 15 | if (mod < 2 || mod > 26 || num < 0) |
| 16 | { |
| 17 | return; |
| 18 | } |
| 19 | |
| 20 | uint32 length, temp; |
| 21 | |
| 22 | // 进制转换 |
| 23 | length = 0; |
| 24 | while (num) |
| 25 | { |
| 26 | temp = num % mod; |
| 27 | num /= mod; |
| 28 | numStr[length] = temp > 9 ? temp - 10 + 'A' : temp + '0'; |
| 29 | ++length; |
| 30 | } |
| 31 | |
| 32 | // 特别处理num=0的情况 |
| 33 | if (!length) |
| 34 | { |
| 35 | numStr[0] = '0'; |
| 36 | ++length; |
| 37 | } |
| 38 | |
| 39 | // 将字符串倒转，使得numStr[0]保存的是num的高位数字 |
| 40 | for (int i = 0, j = length - 1; i < j; ++i, --j) |
| 41 | { |
| 42 | swap(numStr[i], numStr[j]); |
| 43 | } |
| 44 | |
| 45 | numStr[length] = '\0'; |
| 46 | } |
| 47 | |
| 48 | void memset(void *memory, char value, int length) |
| 49 | { |