Function getMoneySpent

Hackerrank_problems/ElectronicShop/solution2.py:26–37

(keyboards, drives, b)

#getMoneySpent() will return the amount required to buy the most expensive keyboard and USB drive. If not not possible returns -1.
def getMoneySpent(keyboards, drives, b):
    moneyspent=-1           #maximum amount of money spent
    drives.sort()
    for num in keyboards:
        price=check(drives,0,m-1,b-num,-1)      #price=price of most expensive USB drive that can be bought after purchasing the keyboard of price num
        if price==-1:
            continue
        exp=price+num       #exp=expense after buying both the items
        if exp>moneyspent:
            moneyspent=exp

    return moneyspent


#input part fot the given problem