Function catAndMouse

Hackerrank_problems/Cats and a Mouse/solution.py:7–13

(x, y, z)

import sys

def catAndMouse(x, y, z):
    if(abs(z-x)==abs(z-y)):   # checking whether both the cats reach at the same time or not
        return "Mouse C"      # if yes, returns Mouse C
    elif(abs(z-x)>abs(z-y)):  # checking if the cat B reaches earlier or Cat A
        return "Cat B"
    else:
        return "Cat A"

if __name__ == '__main__':
    fptr = open(os.environ['OUTPUT_PATH'], 'w')