Method
merge
(long arr[],long s,long m, long e)
Source from the content-addressed store, hash-verified
| 24 | } |
| 25 | |
| 26 | public static long merge(long arr[],long s,long m, long e) |
| 27 | { |
| 28 | int n1=(int)(m-s+1);//5 |
| 29 | int n2=(int)(e-m);//5 |
| 30 | long L[]=new long[n1]; |
| 31 | long R[]=new long[n2]; |
| 32 | long count=0; |
| 33 | // Creating a subarray! |
| 34 | for(int i=0;i<n1;i++) |
| 35 | { |
| 36 | L[i]=arr[(int)(s)+i]; |
| 37 | } |
| 38 | for(int j=0;j<n2;j++) |
| 39 | { |
| 40 | R[j]=arr[(int)(m)+1+j]; |
| 41 | } |
| 42 | int i=0,j=0,k=(int)(s); |
| 43 | while(i<n1 && j<n2) |
| 44 | { |
| 45 | if(L[i]<=R[j]) |
| 46 | { |
| 47 | arr[k]=L[i]; |
| 48 | i++; |
| 49 | } |
| 50 | else |
| 51 | { |
| 52 | arr[k]=R[j]; |
| 53 | count+=n1-i; |
| 54 | j++; |
| 55 | } |
| 56 | k++; |
| 57 | } |
| 58 | while(i<n1) |
| 59 | { |
| 60 | arr[k++]=L[i++]; |
| 61 | } |
| 62 | while(j<n2) |
| 63 | { |
| 64 | arr[k++]=R[j++]; |
| 65 | } |
| 66 | return count; |
| 67 | } |
| 68 | } |
Tested by
no test coverage detected