(int left, int right)
| 1 | class Solution { |
| 2 | public int[] closestPrimes(int left, int right) { |
| 3 | // O(R log(logR) + R-L) |
| 4 | |
| 5 | // Sieve algorithm to find prime numbers between [1,right] |
| 6 | boolean prime[] = new boolean[right + 1]; |
| 7 | Arrays.fill(prime,true); |
| 8 | prime[0] = false; |
| 9 | prime[1] = false; |
| 10 | // Sieve-> O(R log(logR)) |
| 11 | for (int p = 2; p * p <= right; p++) { |
| 12 | if (prime[p]) { |
| 13 | for (int i = p * p; i <= right; i += p) |
| 14 | prime[i] = false; |
| 15 | } |
| 16 | } |
| 17 | // R-L |
| 18 | // find min diff b/w pair of prime numbers |
| 19 | int res[] = new int[]{-1,-1}; |
| 20 | int minDiff = Integer.MAX_VALUE; |
| 21 | int prev=-1; |
| 22 | for (int i = left; i <= right; i++) { |
| 23 | if (prime[i]){ |
| 24 | if(prev == -1){ |
| 25 | prev = i; |
| 26 | }else{ |
| 27 | if(i - prev < minDiff){ |
| 28 | res[0] = prev; |
| 29 | res[1] = i; |
| 30 | minDiff = i-prev; |
| 31 | } |
| 32 | prev=i; |
| 33 | } |
| 34 | } |
| 35 | } |
| 36 | return res; |
| 37 | } |
| 38 | } |
nothing calls this directly
no outgoing calls
no test coverage detected